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6x+20+2x^2-5x=180
We move all terms to the left:
6x+20+2x^2-5x-(180)=0
We add all the numbers together, and all the variables
2x^2+x-160=0
a = 2; b = 1; c = -160;
Δ = b2-4ac
Δ = 12-4·2·(-160)
Δ = 1281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1281}}{2*2}=\frac{-1-\sqrt{1281}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1281}}{2*2}=\frac{-1+\sqrt{1281}}{4} $
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